Okay guys. Noob question. I get the concept of backspacing, but how does it work? Like, I read one guy saying that he has 3.8 inch backspacing and then another saying he has 4.75 inch backspacing.
My question: What does that mean? Is 3.8 sticking out of the fender more than 4.75 or the other way around?
Thanks guys!
Backspacing (BS) is the distance from the part of the rim that bolts to the truck's hub, to the far side of the inner (Brake side) lip of the rim.
Crappy Pic:
The line where the angle iron in the pic crosses a length on the ruler in the rim's bowl, is the backspacing for that rim. (The depth of the bowl that the above ruler would be measuring)
So, if the brake-side of the rim's bowl is deeper, that means it has MORE BS.
The more BS, the more of the rim is pulled over the brakes, so, the less the rim STICKS OUT.
If the bowl is shallower, it means the rim sticks out MORE...and that there's LESS BS.
So, just remember that BS is the bowl's depth, and, the deeper the bowl, the more BS, and the tighter the rim is tucked into the well.
So, a rim with 3" of BS sticks out more than one with 4" of BS.
On 2000 - 2004 X's for example, 5.5" of BS gives the most FRONT tire clearance. This is because the front is IFS, and STEERS, and, the less BS, the wider the arc the tire swings through, hitting more stuff in the way.
On the X's REAR, it is a live axle, and less BS gives MORE tire clearance.
This is one reason why some of us use 5.5" BS in front, to be able to fit larger tires, but add rim pacers to the rear to DECREASE the BS, and increase REAR tire room.
I ran 5.5" BS rims for the 5 mounted tires on my 2001 X for example, but used 1.5" spacers on the rear hubs...to reduce the rear BS to 4".